(y^2-4)(5y^2-2y+4)=

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Solution for (y^2-4)(5y^2-2y+4)= equation: 


Simplifying
(y2 + -4)(5y2 + -2y + 4) = 0

Reorder the terms:
(-4 + y2)(5y2 + -2y + 4) = 0

Reorder the terms:
(-4 + y2)(4 + -2y + 5y2) = 0

Multiply (-4 + y2) * (4 + -2y + 5y2)
(-4(4 + -2y + 5y2) + y2(4 + -2y + 5y2)) = 0
((4 * -4 + -2y * -4 + 5y2 * -4) + y2(4 + -2y + 5y2)) = 0
((-16 + 8y + -20y2) + y2(4 + -2y + 5y2)) = 0
(-16 + 8y + -20y2 + (4 * y2 + -2y * y2 + 5y2 * y2)) = 0
(-16 + 8y + -20y2 + (4y2 + -2y3 + 5y4)) = 0

Combine like terms: -20y2 + 4y2 = -16y2
(-16 + 8y + -16y2 + -2y3 + 5y4) = 0

Solving
-16 + 8y + -16y2 + -2y3 + 5y4 = 0

Solving for variable 'y'.

The solution to this equation could not be determined.

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